Simplifying and Equivalent Ratios
Questions designed to stretch thinking, reveal misconceptions, and spark mathematical reasoning.
Convince Me That…
Students must construct a mathematical argument for why each statement is true.
Both ratios simplify to 2 : 3. For 4 : 6, divide both parts by 2 to get 2 : 3. For 10 : 15, divide both parts by 5 to get 2 : 3. Since both ratios have the same simplest form, they are equivalent.
Visually, they both represent the same proportion:
The “split point” is in exactly the same place for both.
To handle decimal ratios, multiply both parts by 10 to eliminate the decimals: 0.6 × 10 = 6 and 0.9 × 10 = 9, giving 6 : 9. Then simplify by dividing both parts by 3: 6 ÷ 3 = 2 and 9 ÷ 3 = 3, giving 2 : 3.
You can verify: in the ratio 0.6 : 0.9, the first part is two-thirds of the second (0.6 ÷ 0.9 = \( \frac{2}{3} \)), and in 2 : 3, the first part is also two-thirds of the second (2 ÷ 3 = \( \frac{2}{3} \)). The relationship between the parts is identical, confirming equivalence.
In 3 : 5, for every 3 of the first quantity there are 5 of the second — the first quantity is smaller than the second. In 5 : 3, for every 5 of the first quantity there are 3 of the second — the first quantity is now larger. These describe opposite situations. For example, if a recipe uses flour and sugar in the ratio 3 : 5, you need more sugar than flour. If the ratio were 5 : 3, you’d need more flour than sugar. This is the “order doesn’t matter” misconception — students sometimes treat a : b and b : a as interchangeable.
You can also check numerically: 3 ÷ 5 = 0.6, but 5 ÷ 3 ≈ 1.67. Since 0.6 ≠ 1.67, the ratios are not equivalent. Order matters in ratios — swapping the parts creates a different ratio unless both parts are equal.
To eliminate the fraction, multiply both parts by 2: \( 1\frac{1}{2} \times 2 = 3 \) and \( 2 \times 2 = 4 \), giving 3 : 4. This works because multiplying both parts of a ratio by the same number produces an equivalent ratio.
Alternatively, convert to an improper fraction first: \( 1\frac{1}{2} = \frac{3}{2} \). So the ratio is \( \frac{3}{2} : 2 \), which is the same as \( \frac{3}{2} : \frac{4}{2} \). Since both parts have the same denominator, we can compare the numerators: 3 : 4. When a ratio contains fractions or mixed numbers, the key strategy is to multiply both parts by the lowest common denominator of the fractional parts to obtain whole numbers.
Give an Example Of…
Think carefully — the fourth box is a trap! Give a non-example that looks right but isn’t.
Example: 6 : 8 (multiply both parts by 2)
Another: 9 : 12 (multiply both parts by 3)
Creative: 1 : \( 1.\dot{3} \) or 1 : \( \frac{4}{3} \) (a Unitary Ratio). This is useful for comparison, showing that for every 1 of the first part, there is \( 1\frac{1}{3} \) of the second.
Trap: 4 : 5 — a student might add 1 to each part of 3 : 4, thinking this gives an equivalent ratio. But 4 : 5 ≠ 3 : 4 (since \( \frac{4}{5} = 0.8 \) while \( \frac{3}{4} = 0.75 \)). This is the additive misconception — equivalent ratios are formed by multiplying both parts by the same number, not by adding.
Example: 12 : 18 (12 = 6 × 2, 18 = 6 × 3, and HCF(2, 3) = 1, so HCF(12, 18) = 6)
Another: 6 : 30 (6 = 6 × 1, 30 = 6 × 5, and HCF(1, 5) = 1, so HCF(6, 30) = 6)
Creative: 42 : 54 (42 = 6 × 7, 54 = 6 × 9, and HCF(7, 9) = 1, so HCF(42, 54) = 6 — students rarely think of these less obvious multiples of 6)
Trap: 12 : 24 — a student might think “both are divisible by 6, so the HCF must be 6.” But HCF(12, 24) = 12, not 6. The trap exploits the common-factor-vs-HCF confusion — just because 6 is a common factor doesn’t make it the highest. You must check whether any larger number also divides both parts.
Example: 3 : 7 (HCF(3, 7) = 1, so both parts share no common factor other than 1)
Another: 4 : 9 (HCF(4, 9) = 1)
Creative: 13 : 17 (both are prime numbers, so HCF = 1 — students often assume larger numbers can always be simplified further)
Trap: 9 : 15 — a student might think “9 and 15 don’t share an obvious common factor” because neither is even. But both are divisible by 3: 9 ÷ 3 = 3 and 15 ÷ 3 = 5, so it simplifies to 3 : 5. The “no obvious factor” misconception catches students who only check for a factor of 2 and miss other common factors like 3 or 5.
Example: 12 : 18 and 20 : 30 (both simplify to 2 : 3)
Another: 15 : 25 and 21 : 35 (both simplify to 3 : 5)
Creative: 14 : 49 and 22 : 77 (both simplify to 2 : 7 — 14 ÷ 7 = 2, 49 ÷ 7 = 7; 22 ÷ 11 = 2, 77 ÷ 11 = 7)
Trap: 10 : 15 and 20 : 25 — a student might add 10 to each part to get the second ratio. But 10 : 15 simplifies to 2 : 3, while 20 : 25 simplifies to 4 : 5. Since 2 : 3 ≠ 4 : 5, these are not equivalent. This is the additive misconception again — adding the same number to both parts does not preserve the ratio.
Always, Sometimes, Never
Is the statement always true, sometimes true, or never true? Students should justify their decision with examples.
This is a very common misconception. It is sometimes true, but only in a trivial case. When both parts are already equal (e.g. 3 : 3), adding the same number gives another equal ratio (e.g. 5 : 5), which is still equivalent to 1 : 1. But when the parts differ, it fails: 2 : 5 with 3 added to each gives 5 : 8, and 2 : 5 ≠ 5 : 8 (since \( \frac{2}{5} = 0.4 \) but \( \frac{5}{8} = 0.625 \)).
Equivalent ratios are created by multiplying both parts by the same number, not by adding. This is the additive misconception — one of the most common errors students make when working with ratios.
This is always true. If both parts of a ratio are even, they are both divisible by 2, meaning they share a common factor of 2. A ratio in its simplest form has no common factors other than 1, so any ratio with two even numbers can definitely be simplified further. For example, 8 : 14 can be divided by 2 to give 4 : 7.
Students might think they need to find the HCF to simplify, but recognising that “both even → not simplest form” is a useful shortcut. Note: this does not mean the ratio simplifies by dividing by exactly 2 — the HCF might be larger (e.g. 12 : 8 has HCF 4, not 2).
This is never valid. To keep a ratio equivalent, you must divide (or multiply) both parts by the same number. If you divide the first part by one number and the second part by a different number, you change the relationship between the parts.
For example, starting with 12 : 18 and dividing the first part by 3 and the second by 2 gives 4 : 9, but 12 : 18 = 2 : 3, and 4 : 9 ≠ 2 : 3. This is the “dividing by different numbers” error — the rule is simple: whatever you do to one part, you must do exactly the same to the other.
This is sometimes true, but only for ratios like 1 : 1 where the difference is 0. For most ratios, the difference scales as the ratio scales.
Consider 2 : 5 (difference is 3). If we multiply by 2 to get 4 : 10, the difference becomes 6. If we multiply by 10 to get 20 : 50, the difference becomes 30. The difference multiplies by the same factor as the ratio itself. Focusing on the “gap” rather than the multiplier is a symptom of additive thinking.
Odd One Out
Which is the odd one out? Can you make a case for each one? There’s no single right answer!
(All three ratios are equivalent to 2 : 3)
Explain the Mistake
Each example contains a deliberate error targeting a common misconception. Can you find where and why the reasoning goes wrong?
Answer: 6 : 4
Reasoning: “I divided both parts by 2, so it’s simplified now.”
The student has found an equivalent ratio but has not fully simplified. This is the “partial simplification” misconception — thinking that dividing by any common factor is enough. While 6 : 4 is equivalent to 12 : 8, both 6 and 4 still share a common factor of 2. The HCF of 12 and 8 is 4, so the fully simplified form is 12 ÷ 4 : 8 ÷ 4 = 3 : 2.
To fully simplify a ratio, students should divide both parts by the highest common factor, or keep dividing until no common factors remain. From 6 : 4, dividing by 2 again gives 3 : 2, which is the simplest form since HCF(3, 2) = 1.
Answer: 4 : 16
Reasoning: “I subtracted 20 from both sides. \(24 – 20 = 4\) and \(36 – 20 = 16\).”
The student has applied additive thinking to a multiplicative concept. Simplification requires division, not subtraction. Subtraction changes the ratio entirely.
Correct approach: Find the highest common factor (HCF) of 24 and 36, which is 12. Then divide both parts by 12.
\(24 \div 12 = 2\)
\(36 \div 12 = 3\)
So the simplified ratio is 2 : 3.
Answer: 15 : 18
Reasoning: “I needed to get from 5 to 15, so I added 10. Then I added 10 to the second part as well to keep it fair. 8 + 10 = 18, so the answer is 15 : 18.”
The student has applied the additive misconception. 15 : 18 simplifies to 5 : 6, which is not the same as 5 : 8. Think about mixing paint:
The correct approach is multiplicative: 15 is 3 times 5, so we must multiply 8 by 3 to get 24. The equivalent ratio is 15 : 24.
Answer: 40 : 1
Reasoning: “40 minutes to 1 hour is just 40 to 1. There’s nothing to simplify because they don’t share a common factor.”
The student has made the “different units” error. You cannot compare 40 of one thing to 1 of another directly.
To write this ratio correctly, convert both quantities to the same unit. Since 1 hour = 60 minutes, the ratio becomes 40 : 60.
Now simplify as a fraction: \( \frac{40}{60} = \frac{4}{6} = \frac{2}{3} \).
The simplest form is 2 : 3.