Probing Questions: Simplifying Algebraic Expressions by Collecting Like Terms
Probing Questions

Simplifying Algebraic Expressions by Collecting Like Terms

Questions designed to stretch thinking, reveal misconceptions, and spark mathematical reasoning.

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Convince Me That…

Students must construct a mathematical argument for why each statement is true.

1
Convince me that \( 3a + 2a = 5a \), not \( 6a^2 \)
πŸ’‘ Possible Argument

If we treat \( a \) as an object (like a tile or an unknown length), \( 3a \) means we have 3 of them and \( 2a \) means we have 2 more. Counting them up gives us 5 of the same object (\( 5a \)).

a a a 3a + a a 2a = 5a (Not 6aΒ²)

The error \( 6a^2 \) comes from the “multiply instead of add” misconception. Students multiply the coefficients (\( 3 \times 2 \)) and the variables (\( a \times a \)). But we are adding, not multiplying.

2
Convince me that \( 4x + 3y \) cannot be simplified further
πŸ’‘ Possible Argument

Like terms must share exactly the same variable part. Here \( 4x \) has variable part \( x \) and \( 3y \) has variable part \( y \). Since \( x \) and \( y \) represent different values (or shapes), these are unlike terms. You cannot collect them.

A common mistake is to write \( 7xy \), but this means \( 7 \times x \times y \). You can prove this is wrong by substituting values: if \( x = 2 \) and \( y = 1 \), then \( 4(2) + 3(1) = 11 \), while \( 7(2)(1) = 14 \).

3
Convince me that \( 5p \; – \; 2p + 3p = 6p \)
πŸ’‘ Possible Argument

We collect the \( p \) terms by working with the coefficients in order: \( 5 \; – \; 2 + 3 \). Doing this left to right: \( 5 \; – \; 2 = 3 \), then \( 3 + 3 = 6 \). So the result is \( 6p \).

A common error is the “sign attachment” misconception — students detach the minus sign. For example, calculating \( 5 + 2 + 3 = 10 \), or calculating \( 5 \; – \; (2 + 3) = 0 \). The key is that the sign belongs to the term that follows it: \( -2p \).

4
Convince me that \( x + x = 2x \), not \( x^2 \)
πŸ’‘ Possible Argument

This is the “Invisible One” concept. The term \( x \) is shorthand for \( 1x \). So \( x + x \) really means \( 1x + 1x \), which is \( 2x \).

We only get \( x^2 \) when we multiply variables: \( x \times x = x^2 \). Adding gives you more of the same thing; multiplying changes the power (and the dimension, if we think of area).

🎯

Give an Example Of…

Think carefully — the fourth box is a trap! Give a non-example that looks right but isn’t.

1
Give an example of two like terms
An example
Another example
One no-one else will think of
A sneaky non-example
πŸ’‘ Possible Answers

Example: \( 3x \) and \( 5x \)

Another: \( 2ab \) and \( 7ab \)

Creative: \( -4y^2 \) and \( y^2 \) — like terms don’t need the same coefficient or even the same sign.

Trap: \( 2x \) and \( 2y \) — these have the same coefficient (2) but different variable parts, so they are NOT like terms. Like terms are defined by matching variables, not matching numbers.

2
Give an example of an expression that cannot be simplified by collecting like terms
An example
Another example
One no-one else will think of
A sneaky non-example
πŸ’‘ Possible Answers

Example: \( 3x + 4y \)

Another: \( 2a + 5b \; – \; c \)

Creative: \( x^2 + x + 1 \) — every term involves \( x \), but the powers are different (\( x^2 \), \( x^1 \), \( x^0 \)), so there are no like terms.

Trap: \( 4x + 3x \) — a student might think this can’t be simplified because “4 and 3 are different numbers,” but they simplify to \( 7x \).

3
Give an example of an expression with at least 3 terms that simplifies to a single term
An example
Another example
One no-one else will think of
A sneaky non-example
πŸ’‘ Possible Answers

Example: \( 2x + 3x + x = 6x \)

Another: \( 5a \; – \; 2a \; – \; 3a = 0 \) — simplifies to zero, which counts as a single term!

Creative: \( y \; – \; 3y + y + y = 0 \) — four terms where the coefficients cancel out completely.

Trap: \( 2x + 3y + x \) — simplifies to \( 3x + 3y \), which is two terms. A student combining unlike terms might incorrectly get \( 6xy \).

4 ✦
Give an example of an expression where collecting like terms results in a term with a negative coefficient
An example
Another example
One no-one else will think of
A sneaky non-example
πŸ’‘ Possible Answers

Example: \( 2x \; – \; 5x = -3x \)

Another: \( y \; – \; 4y = -3y \)

Creative: \( 3a \; – \; a \; – \; a \; – \; a \; – \; a = -a \) — start positive, subtract enough to end negative. The result is \( -1a \), or just \( -a \).

Trap: \( 5x \; – \; 3x \) — simplifies to \( 2x \) (positive). A student might assume that any expression with a minus sign gives a negative answer, but \( 5 – 3 \) is positive.

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Always, Sometimes, Never

Is the statement always true, sometimes true, or never true? Students should justify their decision with examples.

1
Simplifying an expression by collecting like terms changes its value
NEVER

Collecting like terms is just rewriting an expression in a more compact, equivalent form. For example, \( 3x + 2x \) and \( 5x \) give exactly the same output for every possible value of \( x \).

This addresses the misconception that simplifying is an action that “alters” the math, rather than just reorganising it.

2
The term \( x \) has a coefficient of \( 0 \)
NEVER

The term \( x \) implies \( 1x \), so the coefficient is 1. If the coefficient were 0, the term would be \( 0x \), which equals 0 (it would vanish entirely).

This targets the “no number means zero” misconception.

3
Collecting like terms reduces the number of terms in an expression
SOMETIMES

TRUE case: \( 3x + 2x + y \) (3 terms) simplifies to \( 5x + y \) (2 terms).

FALSE case: \( 3x + 2y \) (2 terms) stays as \( 3x + 2y \) (2 terms) because there are no like terms. The number of terms only reduces if there were like terms to begin with.

4
The expression \( 3x + 2y \) is equivalent to \( 2y + 3x \)
ALWAYS

Addition is commutative. The order does not change the result. Just as \( 5 + 3 = 3 + 5 \), the expression \( 3x + 2y \) is identical to \( 2y + 3x \).

Caveat: This works for addition. If it were subtraction (\( 3x – 2y \)), we could not simply flip them to \( 2y – 3x \). We would have to keep the sign with the term: \( -2y + 3x \).

πŸ”΄

Odd One Out

Which is the odd one out? Can you make a case for each one? There’s no single right answer!

1
Which is the odd one out?
\( 3x + 2x \)
\( 5a + 2b \)
\( x^2 + 5x \)
πŸ’‘ A Case for Each
\( 3x + 2x \) is the odd one out — it can be simplified to a single term (\( 5x \)). The others contain unlike terms.
\( 5a + 2b \) is the odd one out — it contains two different letters. The others only use the letter \( x \).
\( x^2 + 5x \) is the odd one out — it contains terms with different powers (degree 2 and degree 1).
2
Which is the odd one out?
\( 5x \; – \; 2x \)
\( 3y \; – \; 7y \)
\( 4z \; – \; 4z \)
πŸ’‘ A Case for Each
\( 4z \; – \; 4z \) is the odd one out — it simplifies to **zero**. The others result in non-zero terms.
\( 3y \; – \; 7y \) is the odd one out — it simplifies to a **negative** term (\( -4y \)). The others are positive or zero.
\( 5x \; – \; 2x \) is the odd one out — it simplifies to a **positive** term (\( 3x \)).
3
Which is the odd one out?
\( 2x + 3y \)
\( 3xy \)
\( x^2 + 2x \)
πŸ’‘ A Case for Each
\( 3xy \) is the odd one out — it is a single term (monomial). The others are binomials.
\( 2x + 3y \) is the odd one out — every term is degree 1 (linear). The others contain terms of degree 2.
\( x^2 + 2x \) is the odd one out — it involves only one variable (\( x \)). The others involve two variables.
πŸ”

Explain the Mistake

Each example contains a deliberate error targeting a common misconception. Can you find where and why the reasoning goes wrong?

1
Simplify \( 4m + 3n + 2m \)
A student writes:

Answer: \( 9mn \)

Reasoning: “I added all the numbers together: 4 + 3 + 2 = 9. Then I put the letters together to get mn.”

πŸ” The Mistake

The student has made the “combine everything” error — treating all terms as like terms. \( 4m \) and \( 2m \) are like terms, but \( 3n \) is not. Correct simplification: \( 6m + 3n \).

Also, \( 9mn \) means \( 9 \times m \times n \), which is a product, not a sum. By substituting values (e.g., \( m=2, n=1 \)), you can prove the student’s expression yields a different result from the original.

2
Simplify \( 5b + 3b \)
A student writes:

Answer: \( 8b \) βœ“

Reasoning: “I added the numbers: 5 + 3 = 8. Then I added the letters: b + b = b. So it’s 8b.”

πŸ” The Mistake

The answer is correct, but the reasoning is flawed (“parallel operations” misconception). The student added the coefficients and then separately tried to “add” the letters. Claiming \( b + b = b \) is incorrect; \( b + b \) is actually \( 2b \).

This reasoning is dangerous because if the student tried it on \( 3a + 2b \), they might write \( 5ab \) (adding 3+2 and a+b), which is wrong.

3
Simplify \( 4p – 7p \)
A student writes:

Answer: \( 3p \)

Reasoning: “You can’t do 4 take away 7, so I did 7 take away 4 which is 3.”

πŸ” The Mistake

The student has made the “commutative subtraction” error — assuming you can swap the order of subtraction to make the numbers “nicer.” You cannot.

Think of a number line (or a thermometer): if you start at 4 and go down by 7, you end up at -3. The correct answer is \( -3p \).

4
Simplify \( 2x^2 + 3x \)
A student writes:

Answer: \( 5x^2 \)

Reasoning: “2 plus 3 is 5, and I kept the highest power.”

πŸ” The Mistake

The student assumes \( x^2 \) and \( x \) are like terms because they both use the letter \( x \). But like terms must have the same letter and the same power. \( x^2 \) is a square shape, while \( x \) is a line (or rectangle) shape. You cannot count them as “5 of the same thing”.

2xΒ² xΒ² xΒ² + 3x x x x These are different shapes. We cannot combine them into a single pile of “5”.