Algebra Tiles
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Investigation questions

64 questions. Work through these with the tool above. Set it up puts the tiles on the board for you (↩ undo brings back what was there), and Show on board puts the question on screen, full size.

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First experiments
5 questions
  1. The board shows 3x + 2 βˆ’ x + 4. How many tiles of each kind are there? Predict the simplified expression, then tap the ? to check.

    Teacher notes

    2x + 6. Three green x tiles and one red βˆ’x tile leave 2x; the ones make 2 + 4 = 6. Watch for 8x from students who add every number they can see.

  2. Tap ⇄ Group like terms. Where does the red βˆ’x tile go? Then tap ⊘ Zero pairs. Has the value of the expression changed?

    Teacher notes

    The βˆ’x tile sits under an x tile and the two are ringed as a zero pair. Cancelling it removes 2 tiles but leaves 2x + 6: a zero pair is worth 0, so taking it away changes nothing.

  3. Switch to β–¦ Expand. The board shows (x + 2)(x + 3). Predict how many x tiles the rectangle will need, then press β–Ά Next step until it is full.

    Teacher notes

    5 x tiles: 3 from x Γ— 3 and 2 from 2 Γ— x, with 1 xΒ² and 6 ones, so xΒ² + 5x + 6. Each block is one of the four multiplications.

  4. Switch to β–­ Factorise. You have 1 xΒ², 5 x tiles and 6 ones. Use the steppers to change the sides of the rectangle until all three checks are ticks.

    Teacher notes

    (x + 2)(x + 3), in either order. 2 and 3 work because they multiply to 6 (the ones in the corner) and add to 5 (the x tiles along the two edges).

  5. Switch to βš– Solve. The mat shows 2x + 3 = 11. What would you take away from both sides first? Use Take from both sides, then Γ· Share into groups.

    Teacher notes

    x = 4. Take 3 ones from both sides (2x = 8), then share each side into 2 equal groups: one x tile matches 4 ones.

Collecting like terms
7 questions
  1. 4x + 3 + 2x + 5: type the simplified expression next to ✏ My answer before you group the tiles. Then press Check.

    Teacher notes

    6x + 8. The x tiles and the ones can’t be joined: they are different sizes, so the answer keeps two terms.

  2. Build 2x + 3x yourself from the tray. Is it 5x or 5xΒ²? Look at what the tiles make, then compare them with an xΒ² tile.

    Teacher notes

    5x. Five long tiles side by side are still x tiles. xΒ² is the big square, x Γ— x, not x + x.

  3. xΒ² + 3x + 2xΒ² + x + 4: group the like terms. Why can’t the xΒ² tiles and the x tiles be collected together?

    Teacher notes

    3xΒ² + 4x + 4. An xΒ² tile is a square with side x; an x tile is 1 by x. They are different areas, so they are different terms.

  4. Switch on y tiles. 3x + 2y + x βˆ’ y: which tiles can go together, and which never can?

    Teacher notes

    4x + y. x tiles and y tiles are different lengths, so 4x + y can’t be simplified any further. Students who write 5xy have joined unlike terms.

  5. 2xy + 3x + xy βˆ’ y: how many terms does the simplified answer have?

    Teacher notes

    Three: 3xy + 3x βˆ’ y. The xy tile is a rectangle with sides x and y, which is a different shape from both the x tile and the y tile.

  6. Choose level 3 (x², x and 1) and press 🎲 New question. Type your simplified answer next to ✏ My answer before you touch the tiles. Do five.

    Teacher notes

    Each question has 3 to 5 terms in xΒ², x and 1, some negative. The feedback names the kind of tile that is wrong without giving the answer.

  7. Type 5 + x + 3x βˆ’ 2 + xΒ² and build it. Simplify it. Does the order the terms are written in matter?

    Teacher notes

    xΒ² + 4x + 3. The order doesn’t change the value, because addition can be done in any order; writing xΒ² first, then x, then the number is a convention.

Zero pairs and negatives
5 questions
  1. Build x βˆ’ x with one green and one red tile. What is it worth? Now try 3 βˆ’ 3 and xΒ² βˆ’ xΒ².

    Teacher notes

    0 every time: a tile and its negative make a zero pair.

  2. 5x βˆ’ 2x: before you tap ⇄ Group like terms, how many zero pairs will there be?

    Teacher notes

    2 zero pairs, leaving 3x. Subtracting 2x is the same as adding 2 red x tiles.

  3. 2x βˆ’ 5x: what is left once the zero pairs cancel? Does the answer surprise anyone?

    Teacher notes

    βˆ’3x: three red tiles. Students often write 3x because they take the smaller number from the larger.

  4. βˆ’x + 4 βˆ’ 3x βˆ’ 6: group the tiles, cancel the zero pairs, then simplify.

    Teacher notes

    βˆ’4x βˆ’ 2. There are no green x tiles, so all 4 red ones stay: βˆ’4x. The ones leave 2 red.

  5. Build an expression of exactly 10 tiles that is worth 0. Can you use three different kinds of tile? Why must the number of tiles be even?

    Teacher notes

    For example xΒ² + 2x + 2 βˆ’ xΒ² βˆ’ 2x βˆ’ 2 (10 tiles). An expression worth 0 is made only of zero pairs, and each pair is 2 tiles, so the count is always even.

Substitution
5 questions
  1. Tap x = …. With x = 3, what is each tile worth? Predict the value of 2x + 5 before you tap the ?.

    Teacher notes

    11. Each x tile shows 3 and each 1 shows 1, so 3 + 3 + 5 = 11. Watch for 2x read as “23”.

  2. The same expression with x = βˆ’2. What does an x tile show now? What is 2x + 5 worth?

    Teacher notes

    1. Each x tile shows βˆ’2, so βˆ’2 + (βˆ’2) + 5 = 1.

  3. 3x + 2 βˆ’ x with x = 4: work out the value as written, then the value of the simplified expression. Why must they be the same?

    Teacher notes

    10 both times: 12 + 2 βˆ’ 4 = 10 and 2 Γ— 4 + 2 = 10. Simplifying never changes the value, whatever x is.

  4. xΒ² + 2x with x = βˆ’3: what does the xΒ² tile show? What is the expression worth?

    Teacher notes

    The xΒ² tile shows 9, because (βˆ’3) Γ— (βˆ’3) is positive, and 2x is βˆ’6, so xΒ² + 2x = 3. Students who type βˆ’3Β² into a calculator get βˆ’9.

  5. Find a value of x that makes 2x + 5 and 4x βˆ’ 1 worth the same. Use x = … on one, then build the other.

    Teacher notes

    x = 3: both are worth 11. This is the equation 2x + 5 = 4x βˆ’ 1, and βš– Solve gives the same answer.

Expanding single brackets
5 questions
  1. 3(x + 4): predict the expansion, then tap each ? block to fill it.

    Teacher notes

    3x + 12. Each of the 3 rows is a copy of x + 4: three x tiles and 3 Γ— 4 = 12 ones.

  2. A student writes 3(x + 4) = 3x + 4. Their answer has been checked next to ✏ My answer. What does the rectangle show they missed?

    Teacher notes

    They multiplied the x but not the 4: the corner holds 12 ones, not 4. 3(x + 4) = 3x + 12.

  3. 2(x βˆ’ 3): what colour will the ones in the rectangle be? Fill it and see.

    Teacher notes

    Red: 2 Γ— (βˆ’3) = βˆ’6, so 2(x βˆ’ 3) = 2x βˆ’ 6.

  4. x(x + 5): what goes in the big block, and why is it a square?

    Teacher notes

    x Γ— x = xΒ², a square with side x. x(x + 5) = xΒ² + 5x.

  5. βˆ’2(x βˆ’ 4): predict the colour of every tile in the rectangle before you fill it.

    Teacher notes

    βˆ’2 Γ— x makes 2 red x tiles and βˆ’2 Γ— (βˆ’4) makes 8 green ones: βˆ’2x + 8. The usual slip is βˆ’2x βˆ’ 8.

Expanding double brackets
7 questions
  1. (x + 1)(x + 4): β–¦ Label blocks is on. Fill the rectangle. Which two blocks hold x tiles?

    Teacher notes

    The two thin blocks: x Γ— 4 = 4x and 1 Γ— x = x, so xΒ² + 5x + 4. The labelled blocks are the grid method.

  2. A student says (x + 3)Β² = xΒ² + 9. Their answer has been checked. Fill the rectangle: what is missing?

    Teacher notes

    xΒ² + 6x + 9. The two blocks of 3 x tiles are what xΒ² + 9 leaves out.

  3. (x + 2)(x βˆ’ 3): before you fill anything, which blocks will be red?

    Teacher notes

    The x Γ— (βˆ’3) block (3 red x tiles) and the 2 Γ— (βˆ’3) corner (6 red ones). The 2 green x tiles cancel 2 red ones: xΒ² βˆ’ x βˆ’ 6.

  4. (x βˆ’ 2)(x βˆ’ 3): why is the corner green when both numbers are negative?

    Teacher notes

    (βˆ’2) Γ— (βˆ’3) = +6, so xΒ² βˆ’ 5x + 6. Students who think “two negatives make a negative” predict βˆ’6.

  5. (x + 4)(x βˆ’ 4): fill the rectangle. What happens to the x tiles?

    Teacher notes

    4 green and 4 red x tiles make 4 zero pairs, leaving xΒ² βˆ’ 16: the difference of two squares.

  6. (2x + 1)(x + 3): how many xΒ² tiles will there be? Predict the whole answer, then fill it.

    Teacher notes

    2xΒ² + 7x + 3: 2 xΒ² tiles, 6 + 1 = 7 x tiles and 3 ones.

  7. Choose level 4 (With negatives) and press 🎲 New question. Type each answer next to ✏ My answer before you fill the rectangle.

    Teacher notes

    The feedback says which part is wrong: the xΒ² block, the x blocks or the sign of the corner, without giving the answer.

Factorising
8 questions
  1. 3x + 6: you have 3 x tiles and 6 ones. Make a rectangle with all of them. What goes down the side?

    Teacher notes

    3 down the side and x + 2 across the top: 3(x + 2). Taking out a common factor is a rectangle with a plain number on one side.

  2. xΒ² + 7x + 12: which pairs of numbers multiply to 12? Which pair also adds to 7? Use πŸ’‘ Hint if you need it.

    Teacher notes

    3 and 4: (x + 3)(x + 4). The other pairs, 1 and 12 and 2 and 6, add to 13 and 8.

  3. xΒ² βˆ’ 5x + 6: the x tiles are red but the ones are gold. What signs must the two numbers in the brackets have?

    Teacher notes

    Both negative: (x βˆ’ 2)(x βˆ’ 3). They must multiply to +6 and add to βˆ’5.

  4. xΒ² + x βˆ’ 6: there is only one x tile, but the rectangle needs more. Build it anyway. How many zero pairs of x tiles did you need?

    Teacher notes

    (x + 3)(x βˆ’ 2): 3 green and 2 red x tiles make +1, using 2 zero pairs. Adding a zero pair doesn’t change the value, which is why it is allowed.

  5. xΒ² βˆ’ 9: there are no x tiles at all. Can the tiles still make a rectangle?

    Teacher notes

    Yes: (x + 3)(x βˆ’ 3). 3 green and 3 red x tiles are 3 zero pairs: the difference of two squares.

  6. 2xΒ² + 7x + 3: put the two xΒ² tiles in a column. Where do the ones go?

    Teacher notes

    (2x + 1)(x + 3): the three ones fill the corner as 1 Γ— 3. The other way round, (2x + 3)(x + 1), gives 2xΒ² + 5x + 3.

  7. xΒ² + 4x + 5: try every rectangle you can. Then tap the ? next to “Can these tiles make a rectangle?”.

    Teacher notes

    No. The pairs that multiply to 5 are 1 and 5 (sum 6) and βˆ’1 and βˆ’5 (sum βˆ’6); neither adds to 4. It needs completing the square: (x + 2)Β² + 1.

  8. xΒ² + 2x: there are no ones. What are the sides of the rectangle?

    Teacher notes

    x and x + 2: x(x + 2). The common factor is x itself.

Completing the square
4 questions
  1. xΒ² + 6x + 4 can’t make a rectangle. Tap β–‘ Make a square. How many ones does the square need, and how many are missing?

    Teacher notes

    (x + 3)Β² needs 9 ones and there are 4, so 5 are missing: xΒ² + 6x + 4 = (x + 3)Β² βˆ’ 5.

  2. xΒ² + 4x + 7: make a square. This time there are too many ones. What happens to the extra ones?

    Teacher notes

    (x + 2)Β² needs 4 ones, so 3 are left over: xΒ² + 4x + 7 = (x + 2)Β² + 3.

  3. xΒ² βˆ’ 8x + 10: make a square. Why are the ones in the corner gold when the x tiles are red?

    Teacher notes

    (x βˆ’ 4)Β² needs (βˆ’4) Γ— (βˆ’4) = 16 ones, and they are positive. 10 βˆ’ 16 = βˆ’6, so xΒ² βˆ’ 8x + 10 = (x βˆ’ 4)Β² βˆ’ 6.

  4. xΒ² + 5x + 1: try β–‘ Make a square. Why does the tool refuse?

    Teacher notes

    5 x tiles can’t be shared equally between the two sides without cutting a tile in half. On paper it is (x + 5/2)Β² βˆ’ 21/4.

Solving equations
7 questions
  1. x + 5 = 12: what single move leaves x on its own?

    Teacher notes

    Take 5 ones from both sides: x = 7.

  2. 3x + 2 = 14: solve it, saying each move out loud before you tap it. The working is written under the mat.

    Teacher notes

    Take 2 from both sides (3x = 12), share into 3 groups and keep one: x = 4.

  3. 2x βˆ’ 3 = 7: there are red ones on the left and none on the right. Try Take from both sides βˆ’ (βˆ’1). Why does the tool refuse? What can you do instead?

    Teacher notes

    The right side has no βˆ’1 tiles to take away. Add 3 ones to both sides instead; the left then has 3 zero pairs to cancel, giving 2x = 10 and x = 5.

  4. 5x + 2 = 2x + 11: there are x tiles on both sides. What should you take away first?

    Teacher notes

    Take 2x from both sides: 3x + 2 = 11, then 3x = 9 and x = 3. Trying to take 5x would need 5 x tiles on the right.

  5. 3 βˆ’ 2x = 9: solve it. What does Β± Change every sign do, and when do you need it?

    Teacher notes

    x = βˆ’3. After taking 3 from both sides, βˆ’2x = 6; sharing gives βˆ’x = 3, and changing every sign gives x = βˆ’3. Changing every sign is multiplying both sides by βˆ’1.

  6. 2x = 7: share into groups. What goes wrong, and what is x?

    Teacher notes

    7 ones can’t be shared into 2 equal groups of whole tiles: 1 is left over, so x = 7/2 = 3Β½. The tiles can only show whole-number answers.

  7. 3x + 1 = 2x + 5. Before solving, type 4 next to ✏ My answer: x = and press Check. Then try 3. What does the tool tell you each time?

    Teacher notes

    x = 4 works: both sides are 13. x = 3 makes the sides 10 and 11, so the left is too small. Substituting checks an answer without solving.

Misconceptions to expose
6 questions
  1. A student simplifies 2x + 3 to 5x. Their answer has been checked. Use the tiles to explain why it is wrong.

    Teacher notes

    The ones and the x tiles are different sizes, so they can’t be counted together. 2x + 3 is already as simple as it gets.

  2. x Γ— x or x + x: which is xΒ² and which is 2x? Fill this rectangle, then build x + x in βŠ• Simplify.

    Teacher notes

    x Γ— x is the square, xΒ²; x + x is two thin tiles, 2x. They are only equal when x = 0 or x = 2.

  3. (x + 5)Β² = xΒ² + 25? The student’s answer has been checked. Fill the rectangle to see why.

    Teacher notes

    xΒ² + 10x + 25. Squaring a sum isn’t squaring each part: two strips of 5 x tiles are missing.

  4. A student writes βˆ’3(x βˆ’ 2) = βˆ’3x βˆ’ 6. What colour should the corner tiles be?

    Teacher notes

    Green: (βˆ’3) Γ— (βˆ’2) = +6, so βˆ’3(x βˆ’ 2) = βˆ’3x + 6.

  5. 2x + 4 = 10: a student takes 4 from the left side only and writes 2x = 10. Why doesn’t the tool let you do that?

    Teacher notes

    The two sides would stop being equal. Every move in the tool changes both sides, so every line of the working is still true: 2x = 6, then x = 3.

  6. xΒ² + 5x + 6: a student says (x + 5)(x + 6). Their answer has been checked. What were they thinking, and what is wrong?

    Teacher notes

    (x + 5)(x + 6) = xΒ² + 11x + 30. The numbers in the brackets must multiply to the ones (6) and add to the x tiles (5): 2 and 3.

Open investigations
5 questions
  1. Find every expression xΒ² + bx + 12 that makes a rectangle, with b positive. How do you know you have them all?

    Teacher notes

    b = 7, 8 or 13, from the factor pairs 3 Γ— 4, 2 Γ— 6 and 1 Γ— 12. Every rectangle comes from a factor pair of 12, and 12 has three.

  2. Now xΒ² + bx βˆ’ 12. How many values of b work?

    Teacher notes

    Six: b = Β±1, Β±4 and Β±11. Each factor pair of 12 can have its minus sign on either number.

  3. Which is bigger, (x + 1)(x + 5) or (x + 3)Β²? Expand both. Does the answer depend on x?

    Teacher notes

    (x + 3)Β² = xΒ² + 6x + 9 is always 4 more than (x + 1)(x + 5) = xΒ² + 6x + 5, whatever x is. The square has the bigger area.

  4. Make your own equation with x on both sides whose answer is negative. Solve it with the tiles, then check your answer next to ✏ My answer.

    Teacher notes

    For example 2x + 5 = 4x + 9 gives x = βˆ’2. One way to make one is to choose the answer first and build both sides to match.

  5. Design an expression with at least 8 tiles that simplifies to 2x βˆ’ 1. Swap with a partner: can they simplify yours?

    Teacher notes

    Any expression with the right totals works, for example 4x + 3 βˆ’ 2x βˆ’ 4 (13 tiles). Zero pairs can make it as long as you like.