Probing Questions: Simplifying Algebraic Expressions by Collecting Like Terms
Probing Questions

Simplifying Algebraic Expressions by Collecting Like Terms

Questions designed to stretch thinking, reveal misconceptions, and spark mathematical reasoning.

๐Ÿ’ฌ

Convince Me That…

Students must construct a mathematical argument for why each statement is true.

1
Convince me that \( 3a + 2a = 5a \), not \( 6a^2 \)
๐Ÿ’ก Possible Argument

If we treat \( a \) as an object (like a tile or an unknown length), \( 3a \) means we have 3 of them and \( 2a \) means we have 2 more. Counting them up gives us 5 of the same object (\( 5a \)).

a a a 3a + a a 2a = 5a (Not 6aยฒ)

The error \( 6a^2 \) comes from the “multiply instead of add” misconception. Students multiply the coefficients (\( 3 \times 2 \)) and the variables (\( a \times a \)). But we are adding, not multiplying.

2
Convince me that \( 4x + 3y \) cannot be simplified further
๐Ÿ’ก Possible Argument

Like terms must share exactly the same variable part. Here \( 4x \) has variable part \( x \) and \( 3y \) has variable part \( y \). Since \( x \) and \( y \) represent different values (or shapes), these are unlike terms. You cannot collect them.

A common mistake is to write \( 7xy \), but this means \( 7 \times x \times y \). You can prove this is wrong by substituting values: if \( x = 2 \) and \( y = 1 \), then \( 4(2) + 3(1) = 11 \), while \( 7(2)(1) = 14 \).

3
Convince me that \( 5p \; – \; 2p + 3p = 6p \)
๐Ÿ’ก Possible Argument

We collect the \( p \) terms by working with the coefficients in order: \( 5 \; – \; 2 + 3 \). Doing this left to right: \( 5 \; – \; 2 = 3 \), then \( 3 + 3 = 6 \). So the result is \( 6p \).

A common error is the “sign attachment” misconception — students detach the minus sign. For example, calculating \( 5 + 2 + 3 = 10 \), or calculating \( 5 \; – \; (2 + 3) = 0 \). The key is that the sign belongs to the term that follows it: \( -2p \).

4
Convince me that \( x + x = 2x \), not \( x^2 \)
๐Ÿ’ก Possible Argument

This is the “Invisible One” concept. The term \( x \) is shorthand for \( 1x \). So \( x + x \) really means \( 1x + 1x \), which is \( 2x \).

We only get \( x^2 \) when we multiply variables: \( x \times x = x^2 \). Adding gives you more of the same thing; multiplying changes the power (and the dimension, if we think of area).

๐ŸŽฏ

Give an Example Of…

Think carefully — the fourth box is a trap! Give a non-example that looks right but isn’t.

1
Give an example of two like terms
An example
Another example
One no-one else will think of
A sneaky non-example
๐Ÿ’ก Possible Answers

Example: \( 3x \) and \( 5x \)

Another: \( 2ab \) and \( 7ab \)

Creative: \( -4y^2 \) and \( y^2 \) — like terms don’t need the same coefficient or even the same sign.

Trap: \( 2x \) and \( 2y \) — these have the same coefficient (2) but different variable parts, so they are NOT like terms. Like terms are defined by matching variables, not matching numbers.

2
Give an example of an expression that cannot be simplified by collecting like terms
An example
Another example
One no-one else will think of
A sneaky non-example
๐Ÿ’ก Possible Answers

Example: \( 3x + 4y \)

Another: \( 2a + 5b \; – \; c \)

Creative: \( x^2 + x + 1 \) — every term involves \( x \), but the powers are different (\( x^2 \), \( x^1 \), \( x^0 \)), so there are no like terms.

Trap: \( 4x + 3x \) — a student might think this can’t be simplified because “4 and 3 are different numbers,” but they simplify to \( 7x \).

3
Give an example of an expression with at least 3 terms that simplifies to a single term
An example
Another example
One no-one else will think of
A sneaky non-example
๐Ÿ’ก Possible Answers

Example: \( 2x + 3x + x = 6x \)

Another: \( 5a \; – \; 2a \; – \; 3a = 0 \) — simplifies to zero, which counts as a single term!

Creative: \( y \; – \; 3y + y + y = 0 \) — four terms where the coefficients cancel out completely.

Trap: \( 2x + 3y + x \) — simplifies to \( 3x + 3y \), which is two terms. A student combining unlike terms might incorrectly get \( 6xy \).

4 โœฆ
Give an example of an expression where collecting like terms results in a term with a negative coefficient
An example
Another example
One no-one else will think of
A sneaky non-example
๐Ÿ’ก Possible Answers

Example: \( 2x \; – \; 5x = -3x \)

Another: \( y \; – \; 4y = -3y \)

Creative: \( 3a \; – \; a \; – \; a \; – \; a \; – \; a = -a \) — start positive, subtract enough to end negative. The result is \( -1a \), or just \( -a \).

Trap: \( 5x \; – \; 3x \) — simplifies to \( 2x \) (positive). A student might assume that any expression with a minus sign gives a negative answer, but \( 5 – 3 \) is positive.

โš–๏ธ

Always, Sometimes, Never

Is the statement always true, sometimes true, or never true? Students should justify their decision with examples.

1
Simplifying an expression by collecting like terms changes its value
NEVER

Collecting like terms is just rewriting an expression in a more compact, equivalent form. For example, \( 3x + 2x \) and \( 5x \) give exactly the same output for every possible value of \( x \).

This addresses the misconception that simplifying is an action that “alters” the math, rather than just reorganising it.

2
The term \( x \) has a coefficient of \( 0 \)
NEVER

The term \( x \) implies \( 1x \), so the coefficient is 1. If the coefficient were 0, the term would be \( 0x \), which equals 0 (it would vanish entirely).

This targets the “no number means zero” misconception.

3
Collecting like terms reduces the number of terms in an expression
SOMETIMES

TRUE case: \( 3x + 2x + y \) (3 terms) simplifies to \( 5x + y \) (2 terms).

FALSE case: \( 3x + 2y \) (2 terms) stays as \( 3x + 2y \) (2 terms) because there are no like terms. The number of terms only reduces if there were like terms to begin with.

4
The expression \( 3x + 2y \) is equivalent to \( 2y + 3x \)
ALWAYS

Addition is commutative. The order does not change the result. Just as \( 5 + 3 = 3 + 5 \), the expression \( 3x + 2y \) is identical to \( 2y + 3x \).

Caveat: This works for addition. If it were subtraction (\( 3x – 2y \)), we could not simply flip them to \( 2y – 3x \). We would have to keep the sign with the term: \( -2y + 3x \).

๐Ÿ”ด

Odd One Out

Which is the odd one out? Can you make a case for each one? There’s no single right answer!

1
Which is the odd one out?
\( 3x + 2x \)
\( 5a + 2b \)
\( x^2 + 5x \)
๐Ÿ’ก A Case for Each
\( 3x + 2x \) is the odd one out — it can be simplified to a single term (\( 5x \)). The others contain unlike terms.
\( 5a + 2b \) is the odd one out — it contains two different letters. The others only use the letter \( x \).
\( x^2 + 5x \) is the odd one out — it contains terms with different powers (degree 2 and degree 1).
2
Which is the odd one out?
\( 5x \; – \; 2x \)
\( 3y \; – \; 7y \)
\( 4z \; – \; 4z \)
๐Ÿ’ก A Case for Each
\( 4z \; – \; 4z \) is the odd one out — it simplifies to **zero**. The others result in non-zero terms.
\( 3y \; – \; 7y \) is the odd one out — it simplifies to a **negative** term (\( -4y \)). The others are positive or zero.
\( 5x \; – \; 2x \) is the odd one out — it simplifies to a **positive** term (\( 3x \)).
3
Which is the odd one out?
\( 2x + 3y \)
\( 3xy \)
\( x^2 + 2x \)
๐Ÿ’ก A Case for Each
\( 3xy \) is the odd one out — it is a single term (monomial). The others are binomials.
\( 2x + 3y \) is the odd one out — every term is degree 1 (linear). The others contain terms of degree 2.
\( x^2 + 2x \) is the odd one out — it involves only one variable (\( x \)). The others involve two variables.
๐Ÿ”

Explain the Mistake

Each example contains a deliberate error targeting a common misconception. Can you find where and why the reasoning goes wrong?

1
Simplify \( 4m + 3n + 2m \)
A student writes:

Answer: \( 9mn \)

Reasoning: “I added all the numbers together: 4 + 3 + 2 = 9. Then I put the letters together to get mn.”

๐Ÿ” The Mistake

The student has made the “combine everything” error — treating all terms as like terms. \( 4m \) and \( 2m \) are like terms, but \( 3n \) is not. Correct simplification: \( 6m + 3n \).

Also, \( 9mn \) means \( 9 \times m \times n \), which is a product, not a sum. By substituting values (e.g., \( m=2, n=1 \)), you can prove the student’s expression yields a different result from the original.

2
Simplify \( 5b + 3b \)
A student writes:

Answer: \( 8b \) โœ“

Reasoning: “I added the numbers: 5 + 3 = 8. Then I added the letters: b + b = b. So it’s 8b.”

๐Ÿ” The Mistake

The answer is correct, but the reasoning is flawed (“parallel operations” misconception). The student added the coefficients and then separately tried to “add” the letters. Claiming \( b + b = b \) is incorrect; \( b + b \) is actually \( 2b \).

This reasoning is dangerous because if the student tried it on \( 3a + 2b \), they might write \( 5ab \) (adding 3+2 and a+b), which is wrong.

3
Simplify \( 4p – 7p \)
A student writes:

Answer: \( 3p \)

Reasoning: “You can’t do 4 take away 7, so I did 7 take away 4 which is 3.”

๐Ÿ” The Mistake

The student has made the “commutative subtraction” error — assuming you can swap the order of subtraction to make the numbers “nicer.” You cannot.

Think of a number line (or a thermometer): if you start at 4 and go down by 7, you end up at -3. The correct answer is \( -3p \).

4
Simplify \( 2x^2 + 3x \)
A student writes:

Answer: \( 5x^2 \)

Reasoning: “2 plus 3 is 5, and I kept the highest power.”

๐Ÿ” The Mistake

The student assumes \( x^2 \) and \( x \) are like terms because they both use the letter \( x \). But like terms must have the same letter and the same power. \( x^2 \) is a square shape, while \( x \) is a line (or rectangle) shape. You cannot count them as “5 of the same thing”.

2xยฒ xยฒ xยฒ + 3x x x x These are different shapes. We cannot combine them into a single pile of “5”.